Question
Calculate the energy released by 1g of natural uranium assuming 200 MeV is released in each fission event and that the fissionable isotope 235U has an abundance of 0.7% by weight in natural uranium.
Solution
235 g of uranium contains 6.02 × 1023 atoms.
1 g of uranium = `1/235 xx 6.023 xx 10^23` atoms
∴ 0.7 g of uranium = `1/235 xx 6.023 xx 10^23 xx 0.007` atoms
1 atom gives 200 MeV.
∴ Total energy released = `(6.023 xx 10^23 xx 0.007 xx 200 xx 10^6 xx 1.6 xx 10^-19)/235 "J" = 5.74 xx 10^8 "J"`
Is there an error in this question or solution?
Solution Calculate the Energy Released by 1g of Natural Uranium Assuming 200 Mev is Released in Each Fission Event and that the Fissionable Isotope 235u Has an Abundance of 0.7% by Weight in Natural Uranium. Concept: Nuclear Energy - Fission.
