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Calculate The De Broglie Wavelength of the Electrons Accelerated Through a Potential Difference of 56 V. - Physics

Calculate the de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

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Solution

Potential difference, V = 56 V

Planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

Charge on an electron, e = 1.6 × 10−19 C

De Broglie wavelength of an electron accelerating through a potential V, is given by the relation:

`lambda = 12.27/ sqrt(V)` Å

`= 12.27/sqrt56 xx 10^(-10) m`

= 0.1639 nm

Therefore, the de Broglie wavelength of each electron is 0.1639 nm.

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APPEARS IN

NCERT Class 12 Physics Textbook
Chapter 11 Dual Nature of Radiation and Matter
Q 12.2 | Page 408
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