Calculate the de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.
Potential difference, V = 56 V
Planck’s constant, h = 6.6 × 10−34 Js
Mass of an electron, m = 9.1 × 10−31 kg
Charge on an electron, e = 1.6 × 10−19 C
De Broglie wavelength of an electron accelerating through a potential V, is given by the relation:
`lambda = 12.27/ sqrt(V)` Å
`= 12.27/sqrt56 xx 10^(-10) m`
= 0.1639 nm
Therefore, the de Broglie wavelength of each electron is 0.1639 nm.