# Calculate and Compare the Energy Released by A) Fusion of 1.0 Kg of Hydrogen Deep Within Sun and B) the Fission of 1.0 Kg of 235u in a Fission Reactor. - Physics

Numerical

Calculate and compare the energy released by a) fusion of 1.0 kg of hydrogen deep within Sun and b) the fission of 1.0 kg of 235U in a fission reactor.

#### Solution

(a) Amount of hydrogen, m = 1 kg = 1000 g

1 mole, i.e., 1 g of hydrogen (""_1^1"H")  contains 6.023 × 1023 atoms.

∴ 1000 g of ""_1^1"H" contains 6.023 × 1023 × 1000 atoms.

Within the sun, four  ""_1^1"H" nuclei combine and form one ""_2^4"He" nucleus. In this process 26 MeV of energy is released.

Hence, the energy released from the fusion of 1 kg ""_1^1"H" is:

"E"_1 = (6.023 xx 10^23 xx 26 xx 10^3)/4

= 39.1495 xx 10^26 " MeV"

(b) Amount of""_92^235"U" = 1 kg = 1000 g

1 mole, i.e., 235 g of  ""_92^235"U" contains 6.023 × 1023 atoms.

∴ 1000 g of ""_92^235"U" contains

(6.023 xx 10^23 xx 1000)/235 "atmos"

It is known that the amount of energy released in the fission of one atom of ""_92^235"U" is 200 MeV.

Hence, energy released from the fission of 1 kg of ""_92^235"U" is:

"E"_2 = (6 xx 10^23 xx1000 xx 200)/235

= 5.106 xx 10^26 " MeV"

therefore "E"_1/"E"_1 = (39.1495 xx 10^26)/(5.106 xx 10^26) = 7.67 ~~ 8

Therefore, the energy released in the fusion of 1 kg of hydrogen is nearly 8 times the energy released in the fission of 1 kg of uranium.

Concept: Nuclear Energy - Nuclear Fission
Is there an error in this question or solution?
Chapter 13: Nuclei - Exercise [Page 466]

#### APPEARS IN

NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 13.30 | Page 466
NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 30 | Page 466
Share