# Calculate the boiling point of solution when 4g of MgSO4 (M= 120 g mol-1) was dissolved in 100g of water, assuming MgSO4 undergoes complete ionization. - Chemistry

Calculate the boiling point of solution when 4g of MgSO4 (M= 120 g mol-1) was dissolved in 100g of water, assuming MgSO4 undergoes complete ionization. (Kb for water = 0.52 K kgmol-1)

#### Solution

Given:

Kb =  0.52 K kg mol-1

Mass of MgSO4 (solute) = 4 g

Mass of Water (Solvent) = 100 g

Molarity of solution =

(4/12)/(100/1000)= 0.33 " mol/L"

MgSO4 undergoes complete ionisation, So, i = 2

Elevation in boiling point is given as,

ΔTb = i x Kb x m

= 2 x 0.52 x 0.33 = 0.34 K

Tf  = 373.15 + 034

= 373.49 K

Boiling point of the solution is 373.49 K.

Concept: Colligative Properties and Determination of Molar Mass - Elevation of Boiling Point
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