Calculate the % atom economy for the following reaction with respect to acetophenone.
C6H6+CH3COCl = C6H5COCH3+HCl
Molecular weight of Products= 12x6+1x5+12+16+12+1x3= 120
Molecular Weight of Reactants= 12x6+1x6+12+1x3+12+16+35.5= 156.5
Required: %Atom economy= ?
Formula: %Atom economy = `"molecular weight of the product"/"total molecular weight of the reactants"xx100`
%Atom economy= `120/156.5xx100`
%Atom economy= 76.677