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Calculate Activation Energy for a Reaction of Which Rate Constant Becomes Four Times When Temperature Changes from 30 °C to 50 °C - Chemistry

Calculate activation energy for a reaction of which rate constant becomes four times when temperature changes from 30 °C to 50 °C. (Given R = 8.314 JK−1 mol−1). 

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Solution

Calculation of activation energy:

Given: T1 = 30° C = 303 K, T2 = 50° C = 323 K

Rate constant becomes four times when temperature changes from 30° C to 50° C.

∴ k2 = 4k1

or `k_2/k_1 = 4`

To find: Activation energy (Ea)

 

 

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