Calculate activation energy for a reaction of which rate constant becomes four times when temperature changes from 30 °C to 50 °C. (Given R = 8.314 JK^{−1} mol^{−1}).

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#### Solution

Calculation of activation energy:

Given: T_{1} = 30° C = 303 K, T_{2} = 50° C = 323 K

Rate constant becomes four times when temperature changes from 30° C to 50° C.

∴ k_{2} = 4k_{1}

or `k_2/k_1 = 4`

To find: Activation energy (E_{a})

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