Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3(s) + 2 HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l) - Chemistry

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3(s) + 2 HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

Solution

0.75 M of HCl ≡ 0.75 mol of HCl are present in 1 L of water

≡ [(0.75 mol) × (36.5 g mol–1)] HCl is present in 1 L of water

≡ 27.375 g of HCl is present in 1 L of water

Thus, 1000 mL of solution contains 27.375 g of HCl.

∴ Amount of HCl present in 25 mL of solution

=(27.375  g)/(1000  mL)xx25  mL

= 0.6844 g

From the given chemical equation,

CaCO3(s) + 2HCL(aq) → CaCl2(aq) + CO2(g) + H2O(l)

2 mol of HCl (2 × 36.5 = 73 g) react with 1 mol of CaCO3 (100 g).

∴ Amount of CaCO3 that will react with 0.6844 g =100/73xx0.6844

= 0.9375 g

Concept: Stoichiometry and Stoichiometric Calculations - Introduction
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