Fill in the blank in the table:
P (A) | P (B) | P (A ∩ B) | P(A∪ B) |
0.5 | 0.35 | ..... | 0.7 |
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Solution
Given: \[P\left( A \right) = \frac{1}{3}, P\left( B \right) = \frac{1}{5} \text{ and } P\left( A \cap B \right) = \frac{1}{15}\]
Given:
P (A) = 0.5, P(B) = 0.35 and P (A ∪ B) = 0.7
By addition theorem, we have:
P (A ∪ B) = P(A) + P (B) - P (A ∩ B)
0.7 = 0.5 + 0.35 - P (A ∩ B)
P (A ∩ B) = 0.5 + 0.35 - 0.7
= 0.85 - 0.7 = 0.15
Concept: Probability - Probability of 'Not', 'And' and 'Or' Events
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