#### Question

C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.

#### Solution

C is the centre of the circle.

Radius = 10 cm

Let the chord be AB.

Distance of the centre to the chord = AB.

CD is perpendiculaar to the chord AB.

Perpendicular drawn from the centre of the circle to the chord bisects the chord.

AD = `"AB"/2 = 12/2` = 6 cm

In Δ ACD,

We apply the Pythagoras theorem

CD² + AD² = AC²

⇒ CD² + 6² = 10²

⇒ CD² + 36² = 100

⇒ CD² = 64

⇒ CD = 8 cm

Thus, distance of the chord from the centre is 8 cm.

Is there an error in this question or solution?

Solution C is the Centre of the Circle Whose Radius is 10 Cm. Find the Distance of the Chord from the Centre If the Length of the Chord is 12 Cm. Concept: Properties of Chord of a Circle.