Question

C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.

Answer 1

C is the centre of the circle.
Radius = 10 cm
Let the chord be AB. 
Distance of the centre to the chord = AB.
CD is perpendiculaar to the chord AB. 
Perpendicular drawn from the centre of the circle to the chord bisects the chord. 

AD = `"AB"/2 = 12/2` = 6 cm

In Δ ACD,
We apply the Pythagoras theorem

CD² + AD² = AC²

⇒ CD² + 6² = 10²

⇒ CD² + 36² = 100

⇒ CD² = 64

⇒ CD = 8 cm 

Thus, distance of the chord from the centre is 8 cm.