C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.
C is the centre of the circle.
Radius = 10 cm
Let the chord be AB.
Distance of the centre to the chord = AB.
CD is perpendiculaar to the chord AB.
Perpendicular drawn from the centre of the circle to the chord bisects the chord.
AD = `"AB"/2 = 12/2` = 6 cm
In Δ ACD,
We apply the Pythagoras theorem
CD² + AD² = AC²
⇒ CD² + 6² = 10²
⇒ CD² + 36² = 100
⇒ CD² = 64
⇒ CD = 8 cm
Thus, distance of the chord from the centre is 8 cm.