HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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# Solution for Find the Total Energy and Binding Energy of an Artificial Satellite of Mass 800 Kg Orbiting at a Height of 1800 Km Above the Surface of the Earth. - HSC Science (Computer Science) 12th Board Exam - Physics

ConceptBinding Energy and Escape Velocity of a Satellite

#### Question

Find the total energy and binding energy of an artificial satellite of mass 800 kg orbiting at a height of 1800 km above the surface of the earth.

[G = 6.67 x 10-11 S.I. units, Radius of earth : R = 6400 km, Mass of earth : M = 6 x 1024 kg]

#### Solution

Given:

h = 1800km = 1.8 × 106m

G = 6.67 × 10-11Nm2/kg2

R = 6400km = 6.4 × 106m

m = 800kg

M = 6 × 1024kg

To find:

T.E = ?

B.E = ?

Formulae:

1. T.E = -(GMm)/(2(R + h))
2. B.E = -T.E

Solution:

T.E = -(GMm)/(2(R + h))

T.E = -(6.67xx10^-11 xx 6 xx 10^24 xx 800)/(2(6.4 + 1.8) xx 10^6)

T.E = -32016 × 107 / 16.4

T.E = -1.952 × 1010 J

Now,

B.E = -T.E

B.E = 1.952 × 1010 J

Is there an error in this question or solution?

#### APPEARS IN

Solution for question: Find the Total Energy and Binding Energy of an Artificial Satellite of Mass 800 Kg Orbiting at a Height of 1800 Km Above the Surface of the Earth. concept: Binding Energy and Escape Velocity of a Satellite. For the courses HSC Science (Computer Science), HSC Science (General) , HSC Science (Electronics)
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