A die is thrown 6 times. If ‘getting an odd number’ is a success, what is the probability of
(i) 5 successes?
(ii) at least 5 successes?
(iii) at most 5 successes?
The repeated tosses of a die are Bernoulli trials. Let X denote the number of successes of getting odd numbers in an experiment of 6 trials.
Probability of getting an odd number in a single throw of a die is p = 3/6 =1/2
`:. q = 1 - p=1/2`
X has a binomial distribution.
(i) P (5 successes) = P (X = 5)
(ii) P(at least 5 successes) = P(X ≥ 5)
(iii) P (at most 5 successes) = P(X ≤ 5)
Video Tutorials For All Subjects
- Bernoulli Trials and Binomial Distribution