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# Solution - Calculate the Volume Occupied by 8.8 G of Co2 at 31.1°C and 1 Bar Pressure. R = 0.083 Bar L K–1 Mol–1. - Behaviour of Real Gases:- Deviation from Ideal Gas Behaviour

#### Question

Calculate the volume occupied by 8.8 g of CO2 at 31.1°C and 1 bar pressure.

R = 0.083 bar L K–1 mol–1.

#### Solution 1

It is known that,

pV = m/M  RT

=> V  = (mRT)/(Mp)

Here

m = 8.8 g

R = 0.083 bar LK–1 mol–1

T = 31.1°C = 304.1 K

M = 44 g

p = 1 bar

Thus volume (V) = (8.8 xx 0.083 xx 304.1)/(44xx1)

= 5.04806 L

= 5.05 L

Hence, the volume occupied is 5.05 L.

#### Solution 2

No of Mole of CO_2 (c) = ("Mass of " CO_2)/"Molar Mass"

= (8.8 g)/(44g mol^(-1)) = 0.2 mol

Pressure of CO_2 (P) = 1 "bar"

R = 0.083 "bar " LK^(-1) mol^(-1)

Temperature (T) = 273 + 31.1

= 304.1 K

Since from gas equation  PV = nRT

V = nRT/P = (0.2 xx 0.083 xx 304.1)/ (1 "bar")

= 5.048 L

Is there an error in this question or solution?
Solution Calculate the Volume Occupied by 8.8 G of Co2 at 31.1°C and 1 Bar Pressure. R = 0.083 Bar L K–1 Mol–1. Concept: Behaviour of Real Gases:- Deviation from Ideal Gas Behaviour.
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