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Beena Got Married 8 Years Ago. Today, Her Age is 11/4 Times Her Age at the Time of Marriage. If Her Daughter'S Age is 1/10 Times Her Age, Then Her Daughter'S Age Is: - Mathematics

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MCQ

Beena got married 8 years ago. Today, her age is `1 1/4` is times her age at the time of marriage. If her daughter's age is 1/10 times her age, then her daughter's age is:

Options

  • 3 years

  • 4 years

  • 5 years

  • 2 years

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Solution

4 years

Explanation:

Let Beena's present age is x year.

then Beena's age at the times of marriage = (x − 8)

ATQ, `"x"=5/4("x"-8)`

4x = 5x − 40

x = 40

Beena's daughter age `="x"/10=40/10=4` years

Concept: Average and Age
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