Question

Beena got married 8 years ago. Today, her age is `1 1/4` is times her age at the time of marriage. If her daughter's age is 1/10 times her age, then her daughter's age is:

Options

• 3 years

• 4 years

• 5 years

• 2 years

Answer 1

4 years

Explanation:

Let Beena's present age is x year.

then Beena's age at the times of marriage = (x − 8)

ATQ, `"x"=5/4("x"-8)`

4x = 5x − 40

x = 40

Beena's daughter age `="x"/10=40/10=4` years