Beena Got Married 8 Years Ago. Today, Her Age is 11/4 Times Her Age at the Time of Marriage. If Her Daughter'S Age is 1/10 Times Her Age, Then Her Daughter'S Age Is: - Mathematics
Beena got married 8 years ago. Today, her age is `1 1/4` is times her age at the time of marriage. If her daughter's age is 1/10 times her age, then her daughter's age is:
Let Beena's present age is x year.
then Beena's age at the times of marriage = (x − 8)
4x = 5x − 40
x = 40
Beena's daughter age `="x"/10=40/10=4` years
Concept: Average and Age
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