# Beena Got Married 8 Years Ago. Today, Her Age is 11/4 Times Her Age at the Time of Marriage. If Her Daughter'S Age is 1/10 Times Her Age, Then Her Daughter'S Age Is: - Mathematics

MCQ

Beena got married 8 years ago. Today, her age is 1 1/4 is times her age at the time of marriage. If her daughter's age is 1/10 times her age, then her daughter's age is:

• 3 years

• 4 years

• 5 years

• 2 years

#### Solution

4 years

Explanation:

Let Beena's present age is x year.

then Beena's age at the times of marriage = (x − 8)

ATQ, "x"=5/4("x"-8)

4x = 5x − 40

x = 40

Beena's daughter age ="x"/10=40/10=4 years

Concept: Average and Age
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