CBSE Class 10CBSE
Share
Notifications

View all notifications

In δAbc, D and E Are Points on the Sides Ab and Ac Respectively Such that De || Bc If Ad = 2 Cm, Ab = 6 Cm and Ac = 9 Cm, Find Ae. - CBSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

In ΔABC, D and E are points on the sides AB and AC respectively such that DE || BC

If AD = 2 cm, AB = 6 cm and AC = 9 cm, find AE.

Solution

We have,

AD = 2 cm, AB = 6 cm

∴ DB = AB – AD

= 6 – 2

⇒ DB = 4 cm

And, DE || BC

Therefore, by basic proportionality theorem, we have,

`"AD"/"DB"="AE"/"EC"`

Taking reciprocal on both sides, we get,

`"DB"/"AD"="EC"/"AE"`

`4/2="EC"/"AE"`

Adding 1 on both sides, we get

`4/2+1="EC"/"AE"+1`

`rArr(4+2)/2=("EC"+"AE")/"AE"`

`rArr6/2="AC"/"AE"`         [∵ EC + AE = AC]

`rArr6/2=9/"AE"`              [∵ AC = 9cm]

`"AE"=(9xx2)/6`

⇒ AE = 3 cm

  Is there an error in this question or solution?

APPEARS IN

Video TutorialsVIEW ALL [1]

Solution In δAbc, D and E Are Points on the Sides Ab and Ac Respectively Such that De || Bc If Ad = 2 Cm, Ab = 6 Cm and Ac = 9 Cm, Find Ae. Concept: Basic Proportionality Theorem Or Thales Theorem.
S
View in app×