#### Question

D and E are the points on the sides AB and AC respectively of a ΔABC such that: AD = 8 cm, DB = 12 cm, AE = 6 cm and CE = 9 cm. Prove that BC = 5/2 DE.

#### Solution

We have,

`"AD"/"DB"=8/12=2/3`

And, `"AE"/"EC"=6/9=2/3`

Since, `"AD"/"DB"="AE"/"EC"`

Then, by converse of basic proportionality theorem

DE || BC

In ΔADE and ΔABC

∠A = ∠A [Common]

∠ADE = ∠B [Corresponding angles]

Then, ΔADE ~ ΔABC [By AA similarity]

`therefore"AD"/"AB"="DE"/"BC"` [Corresponding parts of similar Δ are proportional]

`rArr8/20="DE"/"BC"`

`rArr2/5="DE"/"BC"`

`"BC"=5/2" DE"`

Is there an error in this question or solution?

#### APPEARS IN

Solution D and E Are the Points on the Sides Ab and Ac Respectively of a δAbc Such That: Ad = 8 Cm, Db = 12 Cm, Ae = 6 Cm and Ce = 9 Cm. Prove that Bc = 5/2 De. Concept: Basic Proportionality Theorem Or Thales Theorem.