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Find the Principal Values of Sin^(-1) (-1/2) - CBSE (Science) Class 12 - Mathematics

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Question

Find the principal values of `sin^(-1) (-1/2)`

Solution

Let `sin^(-1) (-1/2) = y` Then sin y = `-1/2 = -sin(pi/6) = sin(-pi/6)`

We know that the range of the principal value branch of sin−1 is

`[-pi/2, pi/2]` and sin `(-pi/2) = - 1/2`

Therefore, the principal value of `sin^(-1) (-1/2) is - pi/6`

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 2: Inverse Trigonometric Functions
Q: 1 | Page no. 41
Solution Find the Principal Values of Sin^(-1) (-1/2) Concept: Basic Concepts of Trigonometric Functions.
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