Question

ax² + (4a² - 3b)x - 12 ab = 0

Answer 1

ax² + (4a² - 3b)x - 12 ab = 0
⇒ ax² + 4a²x  - 3bx - 12ab = 0
⇒ ax (x + 4a) - 3b(x + 4a) = 0
⇒ (ax - 3b) (x + 4a) = 0
⇒ x = `(3b)/a or -4a` are two roots of equation.