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# A Gas Cylinder Contains 12 X 1024 Molecules of Oxygen Gas. the Mass of Oxygen Present in the Cylinder. and the Volume of Oxygen at S.T.P. Present in the Cylinder. [O = 16] - ICSE Class 10 - Chemistry

#### Question

A gas cylinder contains 12 x 1024 molecules of oxygen gas.

If Avogadro’s number is 6 x 1023; Calculate:

1)The mass of oxygen present in the cylinder.

2) The volume of oxygen at S.T.P. present in the cylinder. [O = 16]

#### Solution

1) 1 mole oxygen molecule = 6.022 x 1023 molecules

x moles of oxygen molecule = 12 x 1024 molecules

19.93 moles of oxygen molecule = 12 x 1024 molecules.

Number moles of O2 = ("Mass of" O_2)/("Molar mass of " O_2)

Mass of O2 = 32 x 19.93 = 637.76 g

2) 6.022 x 1023 molceules occupies 22.4 L

12 x 1024 molecules occupies = (12 xx 10^24 xx22.4)/(6.022 xx 10^23) = 446.36 L volume

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#### APPEARS IN

Solution A Gas Cylinder Contains 12 X 1024 Molecules of Oxygen Gas. the Mass of Oxygen Present in the Cylinder. and the Volume of Oxygen at S.T.P. Present in the Cylinder. [O = 16] Concept: Avogadro’s Law of Volume.
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