#### Question

What is the shortest wavelength present in the Paschen series of spectral lines?

#### Solution

Rydberg’s formula is given as:

` "hc"/lambda = 21.76 xx 10^(-19) [1/n_1^2 - 1/n_2^2]`

Where,

*h* = Planck’s constant = 6.6 × 10^{−34} Js

*c *= Speed of light = 3 × 10^{8 }m/s

*(n*_{1} and *n*_{2} are integers)

The shortest wavelength present in the Paschen series of the spectral lines is given for values *n*_{1} = 3 and *n*_{2} = ∞.

`"hc"/lambda = 21.76 xx 10^(-19) [1/(3)^2 - 1/(oo)^2]`

`lambda = (6.6 xx 10^(-34) xx 3 xx 10^8 xx 9)/(21.76 xx 10^(-19)`

`= 8.189 xx 10^(-7) m`

= 818.9 nm

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Solution What is the Shortest Wavelength Present in the Paschen Series of Spectral Lines? Concept: Atomic Spectra.