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Which One of the Following Will Have Largest Number of Atoms? - CBSE (Science) Class 11 - Chemistry

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Question

Which one of the following will have largest number of atoms?

(i) 1 g Au (s)

(ii) 1 g Na (s)

(iii) 1 g Li (s)

(iv) 1 g of Cl2(g)

Solution

1 g of Au (s) `=1/197`mol of Au (s)

`=(6.022xx10^23)/197` atoms of Au (s)

= 3.06 × 1021atoms of Au (s)

1 g of Na (s) `=1/23`mol of Na (s)

`=(6.022xx10^23)/23` atoms of Na (s)

= 0.262 × 1023 atoms of Na (s)

= 26.2 × 1021 atoms of Na (s)

1 g of Li (s) `=1/7` mol of Li (s)

`=(6.022xx10^23)/7` atoms of Li (s)

= 0.86 × 1023 atoms of Li (s)

= 86.0 × 1021 atoms of Li (s)

1 g of Cl2 (g) `=1/71` mol of Cl2 (g)

(Molar mass of Cl2 molecule = 35.5 × 2 = 71 g mol–1)

`=(6.022xx10^23)/71` molecules of Cl2 (g)

= 0.0848 × 1023 molecules of Cl2 (g)

= 8.48 × 1021 molecules of Cl2 (g)

As one molecule of Clcontains two atoms of Cl.

Number of atoms of Cl = 2× 8.48 × 1021 =16.96 × 1021   atoms of Cl

Hence, 1 g of Li (s) will have the largest number of atoms.

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Solution Which One of the Following Will Have Largest Number of Atoms? Concept: Atomic and Molecular Masses - Atomic Mass.
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