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Calculate the Released Energy. - CBSE (Science) Class 12 - Physics

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Question

A nucleus with mass number A = 240 and BE/A = 7.6 MeV breaks into two fragments, each of A = 120 with BE/A = 8.5 MeV. Calculate the released energy.

Solution

The binding energy of the nucleus of mass number 240, B1=7.6×240=1824 MeV

The binding energy of each product nucleus, B2=8.5×120=1020 MeV

Then, the energy released as the nuclues breaks is given by 

E=2B2B1=2×10201824=216 MeV

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Solution Calculate the Released Energy. Concept: Atomic Masses and Composition of Nucleus.
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