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Numerical

At a given place, a barometer records 70 cm of Hg. If the mercury in the barometer is replaced by water, what would be resulting in reading? (Density of Hg = 13600 kg/m^{3}; Density of water = 1000 kg/m^{3})

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#### Solution

Height of mercury column = h = 70 cm = 0.70 m

Density of mercury = ρ= 13600 kg/m^{3}Acceleration due to gravity = g = 10 m/s^{2}Pressure = hρg**For water:**Height of water column = h’ =?

Pressure due to water column = P’

Density of water = ρ

_{w}= 1000 kg/m

^{3}

P’ = h’ρ

_{w}g

But, P’ = P

h’ρ

_{w}g = hρg

h’ρ

_{w}= hρ

h’ = `"hρ"/"ρ"_"w"=(0.7xx13600)/1000` = 9.52 m

Concept: Transmission of Pressure in Liquids

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