At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
T = 300 K
π = 1.52 bar
R = 0.083 bar L K−1 mol−1
Applying the relation,
π = CRT
`=>C = pi/RT`
`= (1.52 "bar")/(0.083 " bar " L K^(-1) mol^(-1)xx300 K")`
= 0.061 mol
Since the volume of the solution is 1 L, the concentration of the solution would be 0.061 M.
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