#### Question

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

#### Solution

Here,

*T* = 300 K

π = 1.52 bar

R = 0.083 bar L K^{−1} mol^{−1}

Applying the relation,

π = *C*R*T*

`=>C = pi/RT`

`= (1.52 "bar")/(0.083 " bar " L K^(-1) mol^(-1)xx300 K")`

= 0.061 mol

Since the volume of the solution is 1 L, the concentration of the solution would be 0.061 M.

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Solution At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration? Concept: Expressing Concentration of Solutions.