Assuming Complete Dissociation, Calculate the Ph of the Following Solutions: 0.005 M Naoh - CBSE (Science) Class 11 - Chemistry
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Assuming complete dissociation, calculate the pH of the following solutions:
0.005 M NaOH
`NaOH_(aq) ↔ Na_(aq)^+ + HO_(aq)^(-)`
`[HO^-] = [NaOH]`
`=> [HO^-] = .005`
`pOH = -log[HO^(-)] = -log(.005)`
pOH = 2.30
:. pH = 14 - 2.30
Hence, the pH of the solution is 11.70.
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Solution Assuming Complete Dissociation, Calculate the Ph of the Following Solutions: 0.005 M Naoh Concept: Ionization of Acids and Bases - The pH Scale.