Assuming complete dissociation, calculate the pH of the following solutions: 0.002 M HBr
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Solution
0.002 HBr:
`HBr + H_2O ↔ H_3O^+ + Br^-`
`[H_3O^+] = [HBr]`
`=> [H_3O^+] = .002`
`:. pH = - log [H_3O^+]`
= -log(0.002)
= 2.69
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