Answer 1

Since n = 3, the element belongs to the 3^rd period. It is a p–block element since the last electron occupies the p–orbital.

There are four electrons in the p–orbital. Thus, the corresponding group of the element

= Number of s–block groups + number of d–block groups + number of p–electrons

= 2 + 10 + 4

= 16

Therefore, the element belongs to the 3^rd period and 16^th group of the periodic table. Hence, the element is Sulphur.

Answer 2

n = 3

Thus element belongs to 3rd period, p-block element.

Since the valence shell contains = 6 electrons, group No = 10 + 6 = 16 configuration

=1s² 2s² 2p⁶ 3s²3p⁴  element name is sulphur