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Assign the Position of the Element Having Outer Electronic Configuration In the Periodic Table. Ns2 Np4 For N = 3 - Chemistry

Assign the position of the element having an outer electronic configuration in the periodic table.

ns2 np4 for = 3

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Solution 1

Since n = 3, the element belongs to the 3rd period. It is a p–block element since the last electron occupies the p–orbital.

There are four electrons in the p–orbital. Thus, the corresponding group of the element

= Number of s–block groups + number of d–block groups + number of p–electrons

= 2 + 10 + 4

= 16

Therefore, the element belongs to the 3rd period and 16th group of the periodic table. Hence, the element is Sulphur.

Solution 2

n = 3

Thus element belongs to 3rd period, p-block element.

Since the valence shell contains = 6 electrons, group No = 10 + 6 = 16 configuration

=1s2s2 2p6 3s23p4  element name is sulphur

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NCERT Class 11 Chemistry Textbook
Chapter 3 Classification of Elements and Periodicity in Properties
Q 30.1 | Page 94
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