Maharashtra State BoardHSC Science (General) 11th
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Assign oxidation number atom in the following species. H3BO3 - Chemistry

Numerical

Assign oxidation number atom in the following species.

H3BO3

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Solution

H3BO3

Oxidation number of H = +1

Oxidation number of O = –2

H3BO3 is a neutral molecule.

∴ Sum of the oxidation numbers of all atoms = 0

∴ 3 × (Oxidation number of H) + (Oxidation number of B) + 3 × (Oxidation number of O) = 0

∴ 3 × (+1) + (Oxidation number of B) + 3 × (–2) = 0

∴ Oxidation number of B + 3 – 6 = 0

∴ Oxidation number of B in H3BO3 = +3

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APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 6 Redox Reactions
Exercises | Q 3. (H)(c) | Page 92
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