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Ashu Is X Years Old While His Mother Mrs Veena Is X2 Years Old. Five Years Hence Mrs Veena Will Be Three Times Old as Ashu. Find Their Present Ages. - Mathematics

Ashu is x years old while his mother Mrs Veena is x2 years old. Five years hence Mrs Veena will be three times old as Ashu. Find their present ages.

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Solution

Given that Ashu’s present age is x years and his mother Mrs. Veena is x2 years

Then according to question,

Five years later, Ashu’s is = (x + 5) years

And his mother Mrs. Veena is  = (x2 + 5) years

Thus

x2 + 5 = 3(x + 5)

x2 + 5 = 3x + 15

x2 + 5 - 3x - 15 = 0

x2 - 3x - 10 = 0

x2 - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x - 5)(x + 2) = 0

So, either 

x - 5 = 0

x = 5

Or

x + 2 = 0

x = -2

But, the age can never be negative.

Therefore, when x = 5 then

x2 = (5)2 = 25

Hence, Ashu’s present age is 5years and his mother Mrs. Veena is 25 years.

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 4 Quadratic Equations
Exercise 4.9 | Q 1 | Page 61
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