Arrange the following:

** **In increasing order of basic strength: C_{6}H_{5}NH_{2}, C_{6}H_{5}N(CH_{3})_{2}, (C_{2}H_{5})_{2}NH and CH_{3}NH_{2}

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#### Solution

C_{6}H_{5}N(CH_{3})_{2} is more basic than C_{6}H_{5}NH_{2} due to the presence of the +I effect of two −CH_{3} groups in C_{6}H_{5}N(CH_{3})_{2}. Further, CH_{3}NH_{2} contains one −CH_{3} group while (C_{2}H_{5})_{2}NH contains two −C_{2}H_{5}groups. Thus, (C_{2}H_{5})_{2} NH is more basic than C_{2}H_{5}NH_{2}.

Now, C_{6}H_{5}N(CH_{3})_{2} is less basic than CH_{3}NH_{2} because of the−R effect of −C_{6}H_{5} group.

Hence, the increasing order of the basic strengths of the given compounds is as follows:

C_{6}H_{5}NH_{2} < C_{6}H_{5}N(CH_{3})_{2} < CH_{3}NH_{2 }< (C_{2}H_{5})_{2}NH

Is there an error in this question or solution?

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