Determine the A.P. Whose 3rd Term is 16 and the 7th Term Exceeds the 5th Term by 12. - ICSE Class 10 - Mathematics
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Determine the A.P. Whose 3rd term is 16 and the 7th term exceeds the 5th term by 12.
For given A.P
`t_3 = a + 2d = 16` ....(i)
`t_7 - t_5 = 12`
`=> (a + 6d) - (a = 4d) = 12`
=> 2d = 12
=> d = 6
Substituting the value of din (i) we get
`a + 2 xx 6 = 16`
=> a + 12 = 16
`=> a = 4`
Thus the required A.P = a, a + d, a + 2d, a + 3d,....
= 4, 10, 16, 22,.....
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Solution Determine the A.P. Whose 3rd Term is 16 and the 7th Term Exceeds the 5th Term by 12. Concept: Arithmetic Progression - Finding Sum of Their First ‘N’ Terms..