#### Question

Determine the A.P. Whose 3rd term is 16 and the 7th term exceeds the 5th term by 12.

#### Solution

For given A.P

`t_3 = a + 2d = 16` ....(i)

Now

`t_7 - t_5 = 12`

`=> (a + 6d) - (a = 4d) = 12`

=> 2d = 12

=> d = 6

Substituting the value of din (i) we get

`a + 2 xx 6 = 16`

=> a + 12 = 16

`=> a = 4`

Thus the required A.P = a, a + d, a + 2d, a + 3d,....

= 4, 10, 16, 22,.....

Is there an error in this question or solution?

Solution Determine the A.P. Whose 3rd Term is 16 and the 7th Term Exceeds the 5th Term by 12. Concept: Arithmetic Progression - Finding Sum of Their First ‘N’ Terms..