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Solution for Insert Five Numbers Between 8 and 26 Such that the Resulting Sequence is an A.P. - CBSE (Commerce) Class 11 - Mathematics

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Question

Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.

Solution

Let A1, A2, A3, A4, and A5 be five numbers between 8 and 26 such that

8, A1, A2, A3, A4, A5, 26 is an A.P.

Here, = 8, = 26, n = 7

Therefore, 26 = 8 + (7 – 1) d

⇒ 6d = 26 – 8 = 18

⇒ = 3

A1 = a + d = 8 + 3 = 11

A2 = a + 2d = 8 + 2 × 3 = 8 + 6 = 14

A3 = a + 3d = 8 + 3 × 3 = 8 + 9 = 17

A4 = a + 4= 8 + 4 × 3 = 8 + 12 = 20

A5 = a + 5d = 8 + 5 × 3 = 8 + 15 = 23

Thus, the required five numbers between 8 and 26 are 11, 14, 17, 20, and 23

  Is there an error in this question or solution?

APPEARS IN

 NCERT Mathematics Textbook for Class 11 (with solutions)
Chapter 9: Sequences and Series
Q: 14 | Page no. 185
Solution for question: Insert Five Numbers Between 8 and 26 Such that the Resulting Sequence is an A.P. concept: Arithmetic Progression (A.P.). For the courses CBSE (Commerce), CBSE (Science), CBSE (Arts)
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