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# Solution for In triangleAbc, D and E Are the Mid-points of Ab and Ac Respectively. Find the Ratio of the Areas of δAde and δAbc - CBSE Class 10 - Mathematics

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#### Question

In ΔABC, D and E are the mid-points of AB and AC respectively. Find the ratio of the areas of ΔADE and ΔABC

#### Solution We have, D and E as the mid-points of AB and AC

So, according to the mid-point theorem

DE || BC and DE =1/2BC            ...(i)

In ΔADE and ΔABC

∠A = ∠A [Common]

∠ADE = ∠B [Corresponding angles]

Then, ΔADE ~ ΔABC [By AA similarity]

By area of similar triangle theorem

("Area"(triangleADE))/("Area"(triangleABC))="DE"^2/"BC"^2

=(1/2BC)^2/"BC"^2               [From (i)]

=(1/4BC^2)/"BC"^2

=1/4

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Solution In triangleAbc, D and E Are the Mid-points of Ab and Ac Respectively. Find the Ratio of the Areas of δAde and δAbc Concept: Areas of Similar Triangles.
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