#### Question

\[∆\] LMN is an equilateral triangle. LM = 14 cm. As shown in figure, three sectors are drawn with vertices as centres and radius 7 cm.

Find,

(4) Area of the shaded region.

#### Solution

∆LMN is an equilateral triangle.

∴ LM = MN = LN = 14 cm

∠L = ∠M = ∠N = 90º

(4) Area of the shaded region = Area of ∆LMN − Total area of all the three sectors = 84.87 − 77.01 = 7.86 cm^{2}

Is there an error in this question or solution?

Solution Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, (4) Area of the Shaded Region. Concept: Areas of Sector and Segment of a Circle.