\[∆\] LMN is an equilateral triangle. LM = 14 cm. As shown in figure, three sectors are drawn with vertices as centres and radius 7 cm.
(4) Area of the shaded region.
∆LMN is an equilateral triangle.
∴ LM = MN = LN = 14 cm
∠L = ∠M = ∠N = 90º
(4) Area of the shaded region = Area of ∆LMN − Total area of all the three sectors = 84.87 − 77.01 = 7.86 cm2
Is there an error in this question or solution?
Solution Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, (4) Area of the Shaded Region. Concept: Areas of Sector and Segment of a Circle.