#### Question

Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x^{2} + y^{2} = 4.

#### Solution

The area of the region bounded by the circle, `x^2 + y^2 = 4, x = sqrt3` and the *x*-axis is the area OAB.

The point of intersection of the line and the circle in the first quadrant is .`(sqrt3,1)`

Area OAB = Area ΔOCA + Area ACB

Therefore, required area enclosed = 32 + π3 - 32 = π3 square units

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Solution for question: Find the Area of the Region in the First Quadrant Enclosed by X-axis, Line X = `Sqrt3` Y and the Circle X2 + Y2 = 4. concept: Area Under Simple Curves. For the courses CBSE (Science), CBSE (Arts), CBSE (Commerce)