CBSE (Commerce) Class 12CBSE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution for Find the Area of the Region in the First Quadrant Enclosed by X-axis, Line X = `Sqrt3` Y and the Circle X2 + Y2 = 4. - CBSE (Commerce) Class 12 - Mathematics

Login
Create free account


      Forgot password?

Question

Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.

Solution

The area of the region bounded by the circle, `x^2 + y^2 = 4, x = sqrt3` and the x-axis is the area OAB.

The point of intersection of the line and the circle in the first quadrant is .`(sqrt3,1)`

Area OAB = Area ΔOCA + Area ACB

Therefore, required area enclosed = 32 + π3 - 32 = π3 square units

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2012 to Current)
Chapter 8: Application of Integrals
Q: 6 | Page no. 366
Solution Find the Area of the Region in the First Quadrant Enclosed by X-axis, Line X = `Sqrt3` Y and the Circle X2 + Y2 = 4. Concept: Area Under Simple Curves.
S
View in app×