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# Solution - The vertices of ∆ABC = are A (4, 6), B(1, 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively such that AD/AB=AE/AC=1/4 .Calculate the area of ∆ADE and compare it with the area of ∆ABC - CBSE Class 10 - Mathematics

ConceptArea of a Triangle

#### Question

The vertices of ∆ABC = are A (4, 6), B(1, 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively such that \frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{4} .Calculate the area of ∆ADE and compare it with the area of ∆ABC

#### Solution

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#### Reference Material

Solution for question: The vertices of ∆ABC = are A (4, 6), B(1, 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively such that AD/AB=AE/AC=1/4 .Calculate the area of ∆ADE and compare it with the area of ∆ABC concept: Area of a Triangle. For the course CBSE
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