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# Sides of a Triangle Are in the Ratio of 12: 17: 25 and Its Perimeter is 540 cm. Find Its Area. - CBSE Class 9 - Mathematics

ConceptArea of a Triangle by Heron’S Formula

#### Question

Sides of a triangle are in the ratio of 12: 17: 25 and its perimeter is 540 cm. Find its area.

#### Solution

Let the common ratio between the sides of the given triangle be x.

Therefore, the side of the triangle will be 12x, 17x, and 25x.

Perimeter of this triangle = 540 cm

12x + 17x + 25x = 540 cm

54x = 540 cm

x = 10 cm

Sides of the triangle will be 120 cm, 170 cm, and 250 cm.

s="perimeter of triangle"/2=540/2=270cm

By Heron's formula,

"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))

=[sqrt(270(270-120)(270-170)(270-250))]cm^2

=[sqrt(270xx150xx100xx20)]cm^2

= 9000 cm2

Therefore, the area of this triangle is 9000 cm2.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Mathematics Class 9 (2018 to Current)
Chapter 12: Heron's Formula
Ex. 12.10 | Q: 5 | Page no. 203

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Solution Sides of a Triangle Are in the Ratio of 12: 17: 25 and Its Perimeter is 540 cm. Find Its Area. Concept: Area of a Triangle by Heron’S Formula.
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