CBSE Class 9CBSE
Share
Notifications

View all notifications

Sides of a Triangle Are in the Ratio of 12: 17: 25 and Its Perimeter is 540 cm. Find Its Area. - CBSE Class 9 - Mathematics

Login
Create free account


      Forgot password?

Question

Sides of a triangle are in the ratio of 12: 17: 25 and its perimeter is 540 cm. Find its area.

Solution

Let the common ratio between the sides of the given triangle be x.

Therefore, the side of the triangle will be 12x, 17x, and 25x.

Perimeter of this triangle = 540 cm

12x + 17x + 25x = 540 cm

54x = 540 cm

x = 10 cm

Sides of the triangle will be 120 cm, 170 cm, and 250 cm.

`s="perimeter of triangle"/2=540/2=270cm`

By Heron's formula,

`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`

                          `=[sqrt(270(270-120)(270-170)(270-250))]cm^2`

                          `=[sqrt(270xx150xx100xx20)]cm^2`

                           = 9000 cm2

Therefore, the area of this triangle is 9000 cm2.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Class 9 (2018 to Current)
Chapter 12: Heron's Formula
Ex. 12.10 | Q: 5 | Page no. 203

Video TutorialsVIEW ALL [1]

Solution Sides of a Triangle Are in the Ratio of 12: 17: 25 and Its Perimeter is 540 cm. Find Its Area. Concept: Area of a Triangle by Heron’S Formula.
S
View in app×