#### Question

Find values of *k* if area of triangle is 4 square units and vertices are (*k*, 0), (4, 0), (0, 2)

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#### Solution

We know that the area of a triangle whose vertices are (*x*_{1}, *y*_{1}), (*x*_{2}, *y*_{2}), and (*x*_{3}, *y*_{3}) is the absolute value of the determinant (Δ), where

It is given that the area of triangle is 4 square units.

∴Δ = ± 4.

The area of the triangle with vertices (*k*, 0), (4, 0), (0, 2) is given by the relation

When −*k* + 4 = − 4, *k* = 8.

When −*k* + 4 = 4, *k* = 0.

Hence, *k* = 0, 8.

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#### Reference Material

Solution for question: Find Values Of K If Area of Triangle is 4 Square Units and Vertices Are (K, 0), (4, 0), (0, 2) concept: null - Area of a Triangle. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)