CBSE (Arts) Class 12CBSE
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Solution - Find Values Of K If Area of Triangle is 4 Square Units and Vertices Are (K, 0), (4, 0), (0, 2) - CBSE (Arts) Class 12 - Mathematics

Question

Find values of k if area of triangle is 4 square units and vertices are (k, 0), (4, 0), (0, 2)

 

Solution

We know that the area of a triangle whose vertices are (x1y1), (x2y2), and  (x3y3) is the absolute value of the determinant (Δ), where

It is given that the area of triangle is 4 square units.

∴Δ = ± 4.

The area of the triangle with vertices (k, 0), (4, 0), (0, 2) is given by the relation

When −k + 4 = − 4, k = 8.

When −k + 4 = 4, k = 0.

Hence, k = 0, 8.

Is there an error in this question or solution?

APPEARS IN

 NCERT Mathematics Textbook for Class 12 Part 1 (with solutions)
Chapter 4: Determinants
Q: 3.1 | Page no. 123

Reference Material

Solution for question: Find Values Of K If Area of Triangle is 4 Square Units and Vertices Are (K, 0), (4, 0), (0, 2) concept: null - Area of a Triangle. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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