#### Question

Determine the ratio in which the line 2x + y – 4 = 0 divides the line segment joining the points A(2, – 2) and B(3, 7).

#### Solution

Let the given line divide the line segment joining the points A(2, −2) and B(3, 7) in a ratio *k *: 1

Coordinates of the point of division = ` ((3k+2)/(k+1), (7k-2)/(k+1))`

This point also lies on 2*x* + *y* − 4 = 0

`:.2((3k+2)/(k+1))+((7k-2)/(k+1))-1=0`

`=>(6k+4+7k-2-4k-4)/(k+1)=0`

`=>9k-2=0`

`=>k=2/9`

Therefore, the ratio in which the line 2*x* + *y* − 4 = 0 divides the line segment joining the points A(2, −2) and B(3, 7) is 2:9.

Is there an error in this question or solution?

Solution Determine the Ratio in Which the Line 2x +y – 4 = 0 Divides the Line Segment Joining the Points A(2, – 2) and B(3, 7). Concept: Area of a Triangle.