ConceptArea of a Triangle

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#### Question

Find the values of k so that the area of the triangle with vertices (k + 1, 1), (4, -3) and (7, -k) is 6 sq. units.

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For what value of k are the points (k, 2 – 2k), (–k + 1, 2k) and (–4 – k, 6 – 2k) are collinear ?

Find the area of the quadrilateral whose vertices, taken in order, are (-4, -2), (-3, -5), (3, -2) and (2, 3).

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If the points A(−1, −4), B(*b*, *c*) and C(5, −1) are collinear and 2*b* + *c* = 4, find the values of *b* and *c*.

#### Reference Material

Solution for concept: Area of a Triangle. For the course 8th-10th CBSE