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The Area of a Trapezium is 1586 Cm2 and the Distance Between the Parallel Sides is 26 Cm. If One of the Parallel Sides is 38 Cm, Find the Other. - Mathematics

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ConceptArea of Trapezium

Question

The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.

Solution

Given:
Area of the trapezium = 1586 cm2
Distance between the parallel sides = 26 cm
And, length of one parallel side = 38 cm
Let us suppose the length of the other side to be x cm .
Now, area of the trapezium $=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Distance between the parallel sides })$
$\Rightarrow 1586 =\frac{1}{2}\times(38+x)\times(26)$
$\Rightarrow 1586=\frac{26}{2}\times(38+x)$
$\Rightarrow 13\times(38+x)=1586$
$\Rightarrow 38+x = \frac{1586}{13}=122$
$\Rightarrow x = 122-38=84 cm$
Hence, the length of the other parallel side is 84 cm.
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APPEARS IN

RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.2 | Q: 15 | Page no. 24

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Solution The Area of a Trapezium is 1586 Cm2 and the Distance Between the Parallel Sides is 26 Cm. If One of the Parallel Sides is 38 Cm, Find the Other. Concept: Area of Trapezium.
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