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Find the Area, in Square Metres, of the Trapezium Whose Bases and Altitude is as Under: Bases = 28 Cm and 3 Dm, Altitude = 25 Cm - Mathematics

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ConceptArea of Trapezium

Question

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm

Solution

Given:
Bases:
\[28 cm =\frac{28}{100}m = 0.28 m\]
And, 3 dm \[=\frac{3}{10}m = 0.3 m\]
Altitude = 25 cm\[ =\frac{25}{100}m = 0.25 m\]
Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the bases })\times( \text{ Altitude })\]
\[ = \frac{1}{2} \times (0 . 28 + 0 . 3) m \times (0 . 25) m\]
\[ {= 0.0725 m}^2 \]

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APPEARS IN

 RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.2 | Q: 1.2 | Page no. 22

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Solution Find the Area, in Square Metres, of the Trapezium Whose Bases and Altitude is as Under: Bases = 28 Cm and 3 Dm, Altitude = 25 Cm Concept: Area of Trapezium.
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