#### Question

Find the area, in square metres, of the trapezium whose bases and altitude is as under:

bases = 28 cm and 3 dm, altitude = 25 cm

#### Solution

Given:

Bases:

\[28 cm =\frac{28}{100}m = 0.28 m\]

And, 3 dm \[=\frac{3}{10}m = 0.3 m\]

Altitude = 25 cm\[ =\frac{25}{100}m = 0.25 m\]

Area of trapezium \[=\frac{1}{2}\times(\text{ Sum of the bases })\times( \text{ Altitude })\]

\[ = \frac{1}{2} \times (0 . 28 + 0 . 3) m \times (0 . 25) m\]

\[ {= 0.0725 m}^2 \]

Is there an error in this question or solution?

Solution Find the Area, in Square Metres, of the Trapezium Whose Bases and Altitude is as Under: Bases = 28 Cm and 3 Dm, Altitude = 25 Cm Concept: Area of Trapezium.