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Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm. - Mathematics

Course
ConceptArea of Trapezium

Question

Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.

Solution

Given:
Area of the trapezium=65 cm2
The lengths of the opposite parallel sides are 13 cm and 26 cm.
Area of trapezium$=\frac{1}{2}\times(\text{ Sum of parallel bases })\times(\text{ Altitude })$
On putting the values:
$65 = \frac{1}{2} \times (13 + 26) \times (\text{ Altitude })$
$65 \times 2 = 39 \times\text{ Altitude }$
$\text{ Altitude }=\frac{130}{39}=\frac{10}{3}cm$

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APPEARS IN

RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.2 | Q: 5 | Page no. 22

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Solution Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm. Concept: Area of Trapezium.
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