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The Floor of a Building Consists of 3000 Tiles Which Are Rhombus Shaped and Each of Its Diagonals Are 45 Cm and 30 Cm in Length. Find the Total Cost of Polishing the Floor, - Mathematics

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ConceptArea of a Polygon

Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m2 is Rs 4.

Solution

Given: 
The floor consist of 3000 rhombus shaped tiles . 
The lengths of the diagonals of each tile are 45 cm and 30 cm.
∴Area of a rhombus shaped tile =\[ \frac{1}{2} \times (45 \times 30) = 675 {cm}^2 \]
∴ Area of the complete floor\[ = 3000 \times 675 = 2025000 {cm}^2 \]
Now, we need to convert this area into `m^2` because the rate of polishing is given as per `m^2`.
\[ \therefore 2025000 {cm}^2 = 2025000 \times cm \times cm\]
\[ = 2025000 \times \frac{1}{100} m \times \frac{1}{100} m\]
\[ = 202 . 5 m^2 \]
Now, the cost of polishing 1 `m^2` is Rs 4.
∴ Total cost of polishing the complete floor = 202 . 5 x 4 = 810
Thus, the total cost of polishing the floor is Rs 810.

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APPEARS IN

 RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.1 | Q: 12 | Page no. 14
Solution The Floor of a Building Consists of 3000 Tiles Which Are Rhombus Shaped and Each of Its Diagonals Are 45 Cm and 30 Cm in Length. Find the Total Cost of Polishing the Floor, Concept: Area of a Polygon.
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