# A Flooring Tile Has the Shape of a Parallelogram Whose Base is 24 Cm and the Corresponding Height is 10 Cm. How Many Such Tiles Are Required to Cover a Floor of Area 1080 M2? - Mathematics

#### Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?

#### Solution

Given:
Base of a flooring tile that is in the shape of a parallelogram = b = 24 cm
Corresponding height = h = 10 cm
Now, in a parallelogram:
Area(A) = Base (b) x Height (h)
$\therefore\text{ Area of a tile }= 24 cm \times 10 cm = 240 {cm}^2$
Now, observe that the area of the floor is 1080 $m^2 .$
$1080 m^2 = 1080 \times 1m \times 1m$
$= 1080 \times 100 cm \times 100 cm (\text{ Because }1 m = 100 cm)$
$= 1080 \times 100 \times 100 \times cm \times cm$
$= 10800000 {\text{ cm }}^2$
∴ Number of required tiles =$\frac{10800000}{240} = 45000$
Hence, we need 45000 tiles to cover the floor.

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 20 Mensuration - I (Area of a Trapezium and a Polygon)
Exercise 20.1 | Q 1 | Page 13

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A Flooring Tile Has the Shape of a Parallelogram Whose Base is 24 Cm and the Corresponding Height is 10 Cm. How Many Such Tiles Are Required to Cover a Floor of Area 1080 M2? Concept: Area of a Polygon.