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Using Integration Finds the Area of the Region Bounded by the Triangle Whose Vertices Are (–1, 0), (1, 3) and (3, 2). - CBSE (Science) Class 12 - Mathematics

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Question

Using integration finds the area of the region bounded by the triangle whose vertices are (–1, 0), (1, 3) and (3, 2).

Solution

BL and CM are drawn perpendicular to x-axis.

It can be observed in the following figure that,

Area (ΔACB) = Area (ALBA) + Area (BLMCB) – Area (AMCA) … (1)

Therefore, from equation (1), we obtain

Area (ΔABC) = (3 + 5 – 4) = 4 units

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 8: Application of Integrals
Q: 4 | Page no. 371

Video TutorialsVIEW ALL [1]

Solution Using Integration Finds the Area of the Region Bounded by the Triangle Whose Vertices Are (–1, 0), (1, 3) and (3, 2). Concept: Area Between Two Curves.
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