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(Ii) in the Given Figure, 5 × Pa = 3 × Ab = 30 Cm and Pc = 4cm. Find Cd. - Mathematics

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Question

(ii) In the given figure, 5 × PA = 3 × AB = 30 cm and PC = 4cm. find CD.

Solution

Since two chords AB and CD intersect each other at P.
∴ AP ×  PB =  CP × PD
But 5 × PA = 3 × AB = 30 cm
∴ 5× PA = 30cm ⇒ PA =  6cm
And 3× AB =30cm ⇒ AB = 10cm

⇒ BP = PA + AB  = 6 + 10 = 16 cm

Now,
AP × PB = CP  PD
 ⇒ 6 × 16 = 4 ×PD
⇒ PD = `(6×16)/4` =  24 cm
CD = PD – PC = 24 – 4 = 20 cm

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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 18: Tangents and Intersecting Chords
Exercise 18 (B) | Q: 1.2 | Page no. 283
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(Ii) in the Given Figure, 5 × Pa = 3 × Ab = 30 Cm and Pc = 4cm. Find Cd. Concept: Arc and Chord Properties - If Two Chords Intersect Internally Or Externally Then the Product of the Lengths of the Segments Are Equal.
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