#### Question

In the given figure, AB = AD = DC = PB and ∠DBC = x°. determine, in terms of x : (i) ∠ABD, (ii) ∠APB

Hence or otherwise, prove that AP is parallel to DB.

#### Solution

Given – In the figure, AB = AD = DC = PB and DBC = X

Join AC and BD

To find : the measure of ∠ABD and ∠APB

Proof : ∠DAC = ∠DBC = X

[angels in the same segment]

But ∠DCA = ∠DAC = X [ ∵ AD = DC ]

Also, we have, ∠ABD = ∠DAC [angles in the same segment]

In ∆ABP, ext ∠ABC = ∠BAP + ∠APB

But, ∠BAP = ∠APB [ ∵ AB = BP]

2 × X = ∠APB+ ∠APB = 2∠APB

∴ 2∠APB = 2X

⇒ ∠APB = X

∴ ∠APB = ∠DBC = X ,

But these are corresponding angles

∴ AP || DB

Is there an error in this question or solution?

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In the Given Figure, Ab = Ad = Dc = Pb and ∠Dbc = X°. Determine, in Terms of X : (I) ∠Abd, (Ii) ∠Apb Hence Or Otherwise, Prove that Ap is Parallel to Db. Concept: Arc and Chord Properties - Angles in the Same Segment of a Circle Are Equal (Without Proof).

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