#### Question

In the given circle with diameter AB, find the value of x.

#### Solution

∠ABD = ∠ACD = 30° [Angle in the same segment]

Now in ΔADB ,

∠BAD + ∠ADB + ∠ABD = 180° [angles of a triangle]

But, ∠ADB = 90° [ Angle in a semi-circle]

∴ x + 90° + 30° = 180°

⇒ x = 180° -120°

⇒ x = 60°

Is there an error in this question or solution?

Solution In the Given Circle with Diameter Ab, Find the Value of X. Concept: Arc and Chord Properties - Angles in the Same Segment of a Circle Are Equal (Without Proof).