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In the Given Circle with Diameter Ab, Find the Value of X. - ICSE Class 10 - Mathematics

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Question

In the given circle with diameter AB, find the value of x.

Solution

∠ABD = ∠ACD = 30°              [Angle in the same segment]
Now in  ΔADB ,
∠BAD + ∠ADB + ∠ABD = 180°       [angles of a triangle]
But, ∠ADB = 90° [ Angle in a semi-circle]
∴ x + 90° + 30° = 180°
⇒  x = 180° -120°
⇒  x = 60°

  Is there an error in this question or solution?
Solution In the Given Circle with Diameter Ab, Find the Value of X. Concept: Arc and Chord Properties - Angles in the Same Segment of a Circle Are Equal (Without Proof).
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