#### Question

In the figure, given alongside, CP bisects angle ACB. Show that DP bisects angle ADB.

#### Solution

Given – In the figure, CP is the bisector of ∠ABC

To prove – DP is the bisector of ∠ADB

Proof – Since CP is the bisector of ∠ACB

∴ ∠ACP = ∠BCP

But ∠ACP = ∠ADP [Angle in the same segment

And ∠BCP = ∠BDP

But ∠ACP = ∠BCP

∴ ∠ADP = ∠BDP

∴ DP is the bisector of ∠ADB

Is there an error in this question or solution?

Solution In the Figure, Given Alongside, Cp Bisects Angle Acb. Show that Dp Bisects Angle Adb. Concept: Arc and Chord Properties - Angles in the Same Segment of a Circle Are Equal (Without Proof).