#### Question

In the given figure, A is the centre of the circle, ABCD is a parallelogram and CDE is a straight line.

Prove that : ∠BCD = 2∠ABE .

#### Solution

∠BAD = 2∠BED

(Angle at the centre is double the angle at the circumference subtended by the same chord)

And ∠BED = ∠ABE (alternate angles)

∴ ∠BAD = 2∠ABE ……… (i)

ABCD is a parallelogram

∴ ∠BAD = ∠BCD ………. (ii)

(opposite angles in a parallelogram are equal) From (i) and (ii),

∠BCD = 2∠ABE

Is there an error in this question or solution?

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In the Given Figure, a is the Centre of the Circle, Abcd is a Parallelogram and Cde is a Straight Line. Prove that : ∠Bcd = 2∠Abe . Concept: Arc and Chord Properties - the Angle that an Arc of a Circle Subtends at the Center is Double that Which It Subtends at Any Point on the Remaining Part of the Circle.

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